The catch{} blocks are in a correct order,
because ArithmeticException is not
an ancestor nor a descendant of NumberFormatException.
The other order of the two blocks would also work.
In the example program,
the try{} block
might throw
(1) an IOException,
(2) a NumberFormatException,
or
(3) an ArithmeticException.
public static void main ( String[] a ) throws IOException . . . . try { System.out.println("Enter the numerator:"); inData = stdin.readLine(); num = Integer.parseInt( inData ); System.out.println("Enter the divisor:"); inData = stdin.readLine(); div = Integer.parseInt( inData ); System.out.println( num + " / " + div + " is " + (num/div) ); }
An IOException might occur in either readLine() statement.
There is no try{} block for this type of exception,
so the method has to say throws IOException.
A NumberFormatException might occur in either
parseInt().
The first catch{} block is for this type of exception.
An ArithmeticException might occur if the user enters
data that can't be used in an integer division.
A second a catch{} block is for this type of exception.