Falling Bricks

Gravity pulls upon the brick, causing it to go faster and faster. The distance between the brick and where it was released after t seconds is:

distance = (1/2)*G*t2

• t is the number of seconds since the brick was released.
• G is a constant: 9.80665
• distance is in meters.

For example, after 0.0 seconds, the brick is at 0.0 meters from the release point.

After 1.0 second, the brick is (1/2)*9.80665*(1.0)²   =   0.5 * 9.80665 * 1.0 = 4.903325 meters.

After 2.0 seconds, the brick is at (1/2)*9.80665*(2.0)²   =   0.5 * 9.80665 * 4.0   =   19.6133 meters.

This is getting tedious. It would be nice to have a program to do the calculation for many values of t and print the result as a table.